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sales when he took over to $13 billion when he retired I just sort of got in there and started working, he said modestly42 When asked how he felt about passing the torch, he replied not with some sentiment about the emotions involved, but with his characteristic unsentimental perspective Well, I sure hope the company keeps doing well, he said, because 99 percent of what I own is Walgreen stock I m not very diversified, I can tell you that! 43 In 1998, Jorndt replaced Cork as CEO, too Jorndt decided to retire as CEO in early 2002 and as chairman in 2003, leaving the company in the best shape of its long history David Bernauer became president in 1999 and CEO in 2002 When Jorndt looked back on his run, just months before he left the company, he couldn t remember any particular low-lights, just occasional frustrations I was so mad one time I kicked this fire plug, and I almost broke my foot There s always aggravation If you re never aggravated, the chances are you really don t have your head up and you re not trying very hard You re going to have disappointments You don t hit every ball out of the park You strike out some of the time But it s like going to the dentist: All you remember is the nice smile, you don t remember the pain If you re in retail, a lot of nights you go home and bang your head A lot of things can go wrong and they do But after 39 years, all I remember is the nice smiles The high points for me, really, have just been the people I ve worked with They re in my heart and in my head It s irreplaceable what that has meant to me, these Walgreen people44 Though such a successful CEO at another company would probably hang on or wait for a golden parachute, Jorndt made it a point to leave quietly, while still on top a move he firmly believes is in the best interest of the company.

(r) 1 fjj = P {Xn = j for all n 1 | X0 = j } pji (1 fij )

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Since fjj = 1, we get from this inequality that fij = 1 The inequalities in (351) (k) imply that the sequence {pii , k 1} has a positive Cesaro limit if and only if the (k) sequence {pjj , k 1} has a positive Cesaro limit It now follows from (331) in Theorem 331 that jj < if and only if ii < Theorem 354 Let R be the set of recurrent states of the Markov chain Suppose that the set R is not empty Then (a) the set R is a closed set, (b) the set R can be uniquely split into disjoint irreducible subsets R1 , R2 , (called recurrent subclasses) Proof (a) Choose any state r R Let s be any state such that prs > 0 The set R is closed if we can show that s R Since state r is recurrent and state s is accessible from state r, state r must also be accessible from state s If not, there

would be a positive probability of never returning to state r, contradicting the fact (v) that state r is recurrent Hence there is a positive integer v such that psr > 0 For any integer k,

(v+k+1) (v) (k) psr prr prs , pss (n) (v) (k) implying that pss psr prs prr Since state r is recurrent, it now n=1 k=1 follows from Lemma 351 that state s is recurrent Hence s R (b) We rst observe that the following two properties hold: (P1) If state i communicates with state j and state i communicates with state k, then the states j and k communicate (P2) If state j is recurrent and state k is accessible from state j , then state j is accessible from state k The rst property is obvious The second property was in fact proved in part (a) De ne now for each i R the set C(i) as the set of all states j that communicate with state i The set C(i) is not empty since i communicates with itself by de nition Further, by part (a), C(i) R To prove that the set C(i) is closed, let j C(i) and let k be any state with pjk > 0 Then we must verify that i k and k i From i j and j k it follows that i k Since j i, the relation k i follows when we can verify that k j The relation k j follows directly from property P2, since j is recurrent by the proof of part (a) of Theorem 353 Moreover, the foregoing arguments show that any two states in C(i) communicate It now follows from Lemma 352 that C(i) is an irreducible set Also, using the properties P1 and P2, it is readily veri ed that C(i) = C(j ) if i and j communicate and that C(i) C(j ) is empty otherwise This completes the proof of part (b)

The CAMEL control of SMS in 3GPP R99 relates to the MO-SMS only As from 3GPP Rel-5 onwards, CAMEL control of SMS relates to both MO-SMS and MT-SMS SMS is speci ed mainly in the 3GPP speci cations and reports as listed in Table 52433 The SMS is de ned as a GSM basic service The following basic service (group) codes are allocated to SMS: Teleservice Teleservice Teleservice Teleservice 20 21 22 23 short message service group short message MT (MT-SMS) short message MO (MO-SMS) cell broadcast service

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